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Before this: Charles's law, The mole

The ideal gas law

One equation ties together the four quantities that describe a gas.

P × V = n × R × T

SymbolQuantityUnit
PPressureatm
VVolumeL
nAmountmol
TTemperatureK
RGas constant0.08206 L·atm/(mol·K)

The units must match the units of R. Convert before calculating.

An ideal gas is a model in which particles have no volume and do not attract each other. Real gases follow it closely at ordinary temperatures and pressures, and less well at high pressure or low temperature.

Worked example: volume of 1.00 mol of gas at STP

At STP, T = 273 K and P = 1.00 atm. Solve for V.

V = n × R × T ÷ P

V = 1.00 mol × 0.08206 L·atm/(mol·K) × 273 K ÷ 1.00 atm = 22.4 L

One mole of any ideal gas occupies 22.4 L at STP.

Common mistake

Leaving the temperature in Celsius or the volume in milliliters. With R = 0.08206, pressure must be in atm, volume in L and temperature in K.

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Watch One equation for every case
  1. At STP, 273 K and 1.00 atm, 1 mol of gas fills 22.4 L.
  2. Add a second mole at the same temperature and pressure. The volume doubles to 44.8 L.
  3. Push it back to 22.4 L and the pressure doubles instead, to 2.00 atm.

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Explore An ideal gas

Change the amount, temperature and volume, and watch the pressure.

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Practice

1. What is the pressure of 2.00 mol of gas in a 10.0 L container at 300 K?

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2. How many moles of gas are in a 5.00 L container at 1.50 atm and 298 K?

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3. What volume does 0.500 mol of gas occupy at 1.00 atm and 273 K?

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4. What is the temperature of 1.00 mol of gas at 2.00 atm in a 12.3 L container?

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