Mass-to-mass stoichiometry
Balances measure grams, but equations work in moles. So a mass-to-mass problem always takes three steps.
- Grams to moles of the given substance, using its molar mass.
- Moles to moles, using the mole ratio from the balanced equation.
- Moles to grams of the wanted substance, using its molar mass.
grams A → moles A → moles B → grams B
Worked example: what mass of water forms when 8.00 g of H2 burns?
2 H2 + O2 → 2 H2O
Step 1: 8.00 g H2 ÷ 2.016 g/mol = 3.97 mol H2
Step 2: 3.97 mol H2 × (2 mol H2O / 2 mol H2) = 3.97 mol H2O
Step 3: 3.97 mol H2O × 18.015 g/mol = 71.5 g H2O
Common mistake
Using a mass ratio in place of a mole ratio. The coefficients compare moles, never grams. Going straight from grams of one substance to grams of another skips the step where the equation is actually used.