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Before this: Limiting reactant

Percent yield

percent yield = (actual yield ÷ theoretical yield) × 100

The actual yield is usually lower. Some product sticks to glassware, some reactant does not react, and side reactions make other products.

Worked example: from the two yields

A reaction should produce 25.0 g of product. A student collects 21.5 g.

percent yield = (21.5 g ÷ 25.0 g) × 100 = 86.0%

Worked example: starting from a reactant

2 Mg + O2 → 2 MgO. Burning 12.15 g of Mg gives 18.1 g of MgO. What is the percent yield?

Theoretical yield: 12.15 g ÷ 24.305 g/mol = 0.4999 mol of Mg, which makes 0.4999 mol of MgO. Then 0.4999 mol × 40.304 g/mol = 20.15 g.

percent yield = (18.1 g ÷ 20.15 g) × 100 = 89.8%

Common mistake

Putting the theoretical yield on top. The actual yield goes on top. A result over 100% usually means the product is wet or impure, or the fraction is upside down.

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Watch Actual against theoretical
  1. Stoichiometry says the reaction should produce 25.0 g.
  2. The student actually collects 21.5 g.
  3. Actual over theoretical, times 100: 86.0%.

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Practice

1. The theoretical yield is 40.0 g and the actual yield is 34.0 g. What is the percent yield?

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2. A reaction has a theoretical yield of 12.5 g and a percent yield of 80.0%. What is the actual yield?

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3. CaCO3 → CaO + CO2. Heating 100.0 g of CaCO3 produces 50.4 g of CaO. What is the percent yield?

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4. Which is a reasonable cause of a percent yield below 100%?

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