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Before this: Ions, Chemical formulas

Oxidation numbers

An oxidation number is the charge an atom would have if all its bonds were ionic. It is a bookkeeping tool for following electrons through a reaction.

Rules, applied in order:

  1. An atom in a pure element is 0: Na, O2, Cl2.
  2. A single-atom ion equals its charge: Na+ is +1.
  3. Fluorine is always -1 in compounds.
  4. Hydrogen is +1 when bonded to nonmetals.
  5. Oxygen is usually -2.
  6. The numbers add up to zero in a neutral compound, or to the charge of a polyatomic ion.

The order matters. An earlier rule wins when two conflict. In hydrogen peroxide, H2O2, hydrogen is +1 by rule 4, so each oxygen must be -1 for the total to reach zero.

Worked example: sulfur in H2SO4

Hydrogen is +1 and there are two, giving +2. Oxygen is -2 and there are four, giving -8. The total must be zero.

(+2) + S + (-8) = 0

S = +6

Worked example: manganese in MnO4−

Four oxygens give -8. The total must equal the ion’s charge, -1.

Mn + (-8) = -1

Mn = +7

Common mistake

Forgetting to multiply by the subscript. In H2SO4 the oxygens contribute 4 × (-2) = -8 in total, not -2.

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Watch The oxidation number of sulfur in H2SO4
  1. Hydrogen is +1 and there are two: +2.
  2. Oxygen is −2 and there are four: −8.
  3. The total must be zero, so sulfur makes up the difference: +6.

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Practice

1. What is the oxidation number of each atom in O2?

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2. What is the oxidation number of carbon in CO2?

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3. What is the oxidation number of nitrogen in NO3−?

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4. What is the oxidation number of iron in Fe2O3?

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5. What is the oxidation number of sulfur in SO2? Include the sign.

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